3ax - b = d - 4cx

I am assuming that you need to rewrite the equation with x on a side by itself:

First let us group the terms containing x , on the left sides:

3ax + 4cx = d + b

Now factor x:

x (3a + 4c) = d+b

Now divide by (3a + 4c)

==> x = (d+b)/(3a+4c)

Given a, b, c, and d, you could calculate x value.

Based on the fact that the given expression contains the variable x, we'll determine x.

Fot this rason, we'll move all terms to one side. We'll start by subtracting d both sides:

3ax-b-d = +d-d-4cx

We'll eliminate like terms:

3ax-b-d = -4cx

Now, we'll add 4cx both sides:

3ax-b-d + 4cx = -4cx + 4cx

3ax-b-d + 4cx = 0

We'll combine like terms, namely the terms that contain x and the terms without x:

(3ax+ 4cx) + (-b-d) = 0

We'll factorize by x:

x(3a+4c) + (-b-d) = 0

We'll subtract (-b-d) both sides:

x(3a+4c) = -(-b-d)

x(3a+4c) = b+d

We'll divide by (3a+4c), to isolate x:

**x = ( b+d) / (3a+4c)**

3ax-b =d-4cx.

To solve for x.

Solution:

This is a simple equation containing the variable x. We solve for x.

We collect x's together by adding 4cx to both sides.

3ax-b+4cx = d-4cx+4cx. -4cx+4cx becomes zero.

3ax+4cx -b = d. Add b to both sides:

3ax+4cx -b+b = d+b. -b+b becomes zero on the left.

3ax+4cx = d+b

(3a+4c)x = b+d. 3ax+4cx = (3a+4c)x distributive property of multiplication. d+b =b+d by commutative property of addition.

Divide both sides by 3a+4c.

(3a+4c)x/(3a+4c) = (b+d)/(3a+4c)

x = (b+d)/(3a+4c).