There are many ways to find the slope - the easiest being to put the equation into the slope intercept form, which is
y=mx+b where m represents the slope and b represents the y intercept
To do this, we want to solve the equation 2y-x/3=12 for y
first add x/3 to both sides of the equation to get
2y=12+x/3 or 2y=x/3+12
Our next step would be to divide both sides by 2 but this could be a bit messy with x already being divided by 3. We can eliminate the fraction x/3 by multiplying the entire equation by 3 before doing anything else - this would give us
3(2y=x/3+12) => 6y=x+36
Now if we divide everything by 6 we will isolate the y on the left side of the equation, and the coefficient of the x term will be our slope
y=x/6+6 or we can separate the x/6 and make it a multiplication like this (1/6)x so the equation now looks like this
y=(1/6)x+6 and by looking at the coefficient of x we see that our slope is 1/6.
To find the slope we need to rewrite the function with the standard form y=mx +b where m is the slope
2y -x/3 =12
2y = x/3 +12
Divide by 2:
y= x/6 + 6
Then the slope would be x factor which is 1/6
The slope of a line is the rate of change of y with respect to x. This is given by the derivative `dy/dx` .
To determine slope of the line `2y- x/3 = 12` taken the derivative with respect to x.
`(d(2y- x/3))/dx = (d12)/dx`
`2*dy/dx - (1/3) = 0`
`2*dy/dx = 1/3`
`dy/dx = 1/6`
The slope of the line 2y- x/3 = 12 is 1/6.
To find out the value of the slope, first we have to write that form of the equation of the line where slope is involved.
This form is:
y = mx + n, where m represents the slope
Now, we'll put the given equation into the form above, to emphasize the value of the slope.
2y- x/3 = 12
First step is to isolate y to the left side and to move all terms to the right side, with the changed sign.
2y = 12 + x/3
The next step is to divide both sides, by 2:
y = 6 + x/6
Now, we'll evaluate:
y = mx + n and y = x/6 + 6
For these expressions to be identically, the correspondent coefficients have to be the same:
m = 1/6
n = 6
So, the slope is m = 1/6.
2y-x/3 =12.To find the slope of the line.
The slope of the line is the expressed as the tangent of the angle made by the line with x axis.
The slope of the line ax+by +c = 0 is -a/b or (-coefficient of x)/(coefficient of y).
So the slope of the line 2y-x/3 = 0 Or (1/3)+2y-12 = 0 is = -(-1/3)/3 = 1/9 . The line 2y-x/3 = 12 makes an angle A = arctan (1/9) = 6.34 degree nearly with x axis.
The slope of a line represented by an equation in the form:
y = mx + c
is represented by the constant m in the equation.
To find the slope of given line we transform the equation of the line to the form y = mx +c as follows:
2y - x/3 = 12
2y = x/3 + 12
y = x/3/2 + 12/2
y = (1/6)x +6
Therefore slope of the line is 1/6.