# For 2x -y = 3 find the x and y intercepts.

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An equation for a line can be written in the form x/a + y/b = 1,

where a and b are the x and y intercepts.

2x - y = 3

divide all terms by 3

=> (2/3)x - (1/3)y = (3/3)

=> x / (3/2) + y / (-3) = 1

**Therefore the x intercept is 3/2 and the y intercept is -3**

Given the equation of the line 2x -y = 3

We need to find the x and y intercepts.

Let us determine the x-intercept.

The x-intercept if where the line meet the x-axis. Then, the values of y-coordinate is 0.

Then we will substitute with y= 0

==> 2x-y = 3

==> 2x -0 = 3 ==> x = 3/2

**Then, the x-intercept is the point (3/2, 0)**

Now we will determine the y-intercept.

The y-intercept is the point where the line meets the y-axis. Then, the values of the x-coordinate is 0.

Then we will substitute with x=0 into the equation.

==> 2x-y = 3

==> 0 -y = 3

==> y= -3

**Then, the y-intercept is the point ( 0, -3)**