Solve the system of equations : 2x-y=-2 ; x+3y=13 by elimination method.
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calendarEducator since 2011
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We are asked to solve the system of equations, 2x-y = -2; x+3y =13, by the elimination method.
We will begin by multiplying the first equation by 3. This will result in the coefficients of the y in both equations being additive inverses.
3[2x - y = -2] => 6x -3y = -6
We will now combine the 2 equations.
=> 6x - 3y = -6
x + 3y = 13
=> 7x = 7
=> x = 1
Substitute the x value of 1 into the given equation x + 3y =13 to solve for y.
=> x + 3y = 13
=> 1 + 3y = 13
=> 3y = 12
=> y = 4
The solution set of the system is (1, 4).
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calendarEducator since 2010
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We have to solve the system of equations:
2x - y = -2 ...(1)
x + 3y = 13 ...(2)
1 - 2*(2)
=> 2x - y - 2x - 6y = -2 - 26
=> -7y = -28
=> y = -28/-7
=> y = 4
3*(1) + (2)
=> 6x - 3y + x + 3y = -6 + 13
=> 7x = 7
=> x = 1
The solution of the equation is x = 1 and y = 4