We have to find the values of x and y that satisfy the equations

2x - 3y = 5 and x + 3y = 4

x + 3y = 4

=> x = 4 - 3y

Substitute this in 2x - 3y = 5

=> 2( 4 - 3y) -...

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We have to find the values of x and y that satisfy the equations

2x - 3y = 5 and x + 3y = 4

x + 3y = 4

=> x = 4 - 3y

Substitute this in 2x - 3y = 5

=> 2( 4 - 3y) - 3y = 5

=> 8 - 6y - 3y = 5

=> -9y = -3

=> y = 1/3

x = 4 - 3y = 4 - 3*(1/3) = 4 - 1 = 3

**The required values are x = 3 and y = 1/3.**

Given the system:

2x-3y = 5 .............(1)

x+ 3y = 4................(2)

We have a system of two equations and two variables.

We will use the elimination method to solve for x and y.

We will add (1) and (2).

==> 3x = 9

Now we will divide by 3.

==> x =3

Now we will substitute into (2) to find y.

==> x+ 3y = 4

==> 3 + 3y = 4

==> 3y = 1

==> y= 1/3

Then the solution to the system is :

**x= 3 and y= 1/3**