(2x+3)/(x+2)=3/2Math problem; solve the following rational equation
You need to have all terms to the left side.
Subtracting 3/2 both sides yields:
`(2x+3)/(x+2) - 3/2 = 0`
You need to bring both fractions to a common denominator such that:
`(2(2x+3) - 3(x+2))/(2(x+2)) = 0`
Opening the brackets yields:
`(4x + 6 - 3x - 6)/(2(x+2)) = 0`
`` `x/(2(x+2)) = 0`
The denominator of the fraction must not be zero => `x+2 != 0` => `x != -2` .
If the fraction yields 0 => x = 0.
The solution to the given equation is x = 0.
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