`2x^3 + 3y^3 = 64` Find `dy/dx` by implicit differentiation.

1 Answer

hkj1385's profile pic

hkj1385 | (Level 1) Assistant Educator

Posted on

`2x^3 + 3y^3 = 64`

` `

Differentiating both sides w.r.t 'x' we get

`2*3*x^2 + 3*3*y^2*(dy/dx) = 0`

`or, 2x^2 + 3y^2(dy/dx) = 0`

`or, dy/dx = -(2/3)*(x/y)^2`

``