`2x^3 + 3y^3 = 64`
Differentiating both sides w.r.t 'x' we get
`2*3*x^2 + 3*3*y^2*(dy/dx) = 0`
`or, 2x^2 + 3y^2(dy/dx) = 0`
`or, dy/dx = -(2/3)*(x/y)^2`
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