`2x^2 + 3x = 20` Solve with the quadratic formula.

Expert Answers
lemjay eNotes educator| Certified Educator

A quadratic equation in a form ax^2+bx+c=0 can be solved using the quadratic formula which is:


For the problem above, to be able to apply the quadratic formula, set one side equation equal to zero.




Now that one side of the equation is zero, plug-in the values of a, b and c to the formula. The values are a=2, b=3 and c=-20.





Since the numerator has `+- ` between 3 and 13, the x breaks into two.

`x=(-3+13)/4=10/4=5/2`     and     `x=(-3-13)/4=(-16)/4=-4`

Hence, the solution to `2x^2+3x=20` is `x={-4,5/2}` .

oldnick | Student


`2x^2+3x-20=0 `


Since  `Delta >0`  equation has two different solutions:

`x=(-3+-sqrt(169))/4` `=(-3+-13)/4`      `x_1=5/2`   `x_2=-4`