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If (2x + 1/3x) = 5, then find the value of 5x/(6x^2 + 20x + 1).a.1/7b.16/7c.16/27d.6/27

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`(2x + 1/3x) = 5`

 

`(2xxx3x+1)/3x = 5`

`(6x^2+1) = 15x`

 

`(5x)/(6x^2 + 20x + 1)`

`= (5x)/(6x^2 + 1+20x)`

`= (5x)/(15x+20x)`

`= (5x)/(35x)`

`= 5/35`

`= 1/7`

 

So the answer is` (5x)/(6x^2 + 20x + 1) =1/7`

 

Correct answer is a).

 

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