`2ln(8) + 5ln(z - 4)` Condense the expression to the logarithm of a single quantity.

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loves2learn | (Level 3) Salutatorian

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Bring up the exponents in both terms

`ln8^2+ln(z-4)^5 `

` ` Condense by multiplication

`ln(8^2)(z-4)^2 `

Simplify,

`ln64(z-4)^2 `