a+2b = 2 2a -3b = 4 find a and b.
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a + 2b = 2 ................(1)
2a -3b = 4 .................(2)
We will use the elimination method to solve.
We will multiply (1) by -2 and add to (2).
==> -2a -4b = -4 .....................-2*(1)
==> 2a -3b = 4 .....................(2)
==> -7b = 0 ==> b= 0
Now to calculate a we will substitute into (1).
==> a + 2b = 2 ==> a + 0 + 2 ==> a = 2
==> a = 2
Then the answer to the system is :
a = 2 and b= 0
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calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
We have to solve for a and b given a + 2b = 2 and 2a -3b = 4
a + 2b = 2
=> a = 2 - 2b
Substitute this in 2a - 3b = 4
=> 2( 2 - 2b) - 3b = 4
=> 4 - 4b - 3b = 4
=> -7b = 0
=> b = 0
a = 2 - 2b = 2
Therefore a = 2 and b = 0
Q;
a+2b = 2.......(1)
2a -3b = 4 ....(2)
We have to find a and b.
Solution:
2*(1)-(2): 2(a+2b) - (2a-3b) = 2*2-4 = 0.
4b+3b = 0.
7b = 0.
7b/7 = 0/7.
b= 0.
We put b= 0 in (1): a+2b = 2. So a+2*0 = 2. So a = 2.
a = 2 and b = 0.
a = 2. b = 0.
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