A 27-g piece of aluminum that was originally electrically neutral is given a charge of +1.6 micro coulombs. How many electrons were removed from the aluminum in the charging process?

Expert Answers
justaguide eNotes educator| Certified Educator

An electron has a charge of -1.602*10^-19 C. If a piece of aluminum were given a positive charge of 1.6 micro coulombs electrons were removed from the aluminum during the charging process. Let the number of electrons removed be N.

1.6*10^-6 = N*1.602*10^-19

=> N = 1.6*10^-6*10^19/1.602

=> N = 10^13

Approximately 10^13 electrons have to be removed from a piece of aluminum during the charging process to give it a positive charge of 1.6 micro coulombs.

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question