The reaction that takes place when sodium hydroxide (NaOH) is neutralized by adding hydrogen chloride (HCl) is:
NaOH + HCl --> NaCl + H2O
To neutralize one mole of NaOH one mole of HCl is required. 25 ml of 0.2 M NaOH contains 0.025*0.2 = 0.005 moles of NaOH. As...
See
This Answer NowStart your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Already a member? Log in here.
The reaction that takes place when sodium hydroxide (NaOH) is neutralized by adding hydrogen chloride (HCl) is:
NaOH + HCl --> NaCl + H2O
To neutralize one mole of NaOH one mole of HCl is required. 25 ml of 0.2 M NaOH contains 0.025*0.2 = 0.005 moles of NaOH. As this is neutralized by the addition of 12.5 ml of HCl, there are 0.005 moles of HCl in 12.5 ml of the solution. The molarity of the HCl solution is equal to 0.005/0.0125 = 0.4
The molarity of the HCl solution is 0.4 M