24 more than the quotient of b and 2 is 8. Solve for b.
The quotient of b and 2 is a little ambiguous because division does not have a commutative property. `b-:2!=2-:b` I will solve it for each possibility.
The order of b and 2 implies that the quotient is the quotient of `b-:2` We are told that 24 more than that quotient is 8. From this clue we can formulate the following number sentence:
`(b-:2)+24=8` We subtract 24 from each side of the equation and we get `b-:2=-16` We multiply each side by 2 and we find b=-32.
If they meant the quotient of `2-:b` then our number sentence is:
`(2-:b)+24=8` Again we subtract 24 from each side to get `2-:b=-16` We multiply each side by b and we get `2=-16b` We divide both sides by -16 and `b=-1/8`
The first solution is more likely but both fit the question.
Translating the statement into a math equation, we have:
(b/2) + 24 = 8
So, we would subtract 24 from each side
b/2 = -16
Then, multiply by 2
b = -32
The quotient is the number one gets when one number is divided by another number. What makes your question a little unclear is that I don't know if the quotient is b/2 or 2/b.
If we're looking at b/2, then the question could be solved like this:
With the other scenario of 2/b, then the answer would be solved in this way: