You need to use the following equation to find the vertical height such that:

`v_i = sqrt(2*a*h) => v^2_i = 2*a*h => h = (v^2_i)/(2a)`

`h_v= h*sin 30^o`

d represents the vertical height

a represents the acceleration of the hockey puck...

(The entire section contains 127 words.)

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