# 2. A solution is prepared by diluting 0.785 L of 1.262 M potassium sulfate solution with water to a final volume of 2.00 L. a. How many grams of potassium sulfide were dissolved to make the...

2.

A solution is prepared by diluting 0.785 L of 1.262 M potassium sulfate solution with water to a final volume of 2.00 L.a.

How many grams of potassium sulfide were dissolved to make the original solution?b.

What is the molarity of potassium sulfide in the diluted solution?

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Expert Answers

justaguide | Certified Educator

The solution is prepared by mixing water in 0.785 L of 1.262 M potassium sulfate solution to obtain a final solution with a volume of 2.00 L.

One liter of a 1 M solution of any substance contains one mole of substance in one liter of the solution. 0.785 L of 1.262 M potassium sulfate solution contains 0.785*1.262 = 0.99067 moles of potassium sulfate.

In the final solution the initial amount of potassium sulfate has been dissolved in 2 L of water. This gives a molarity of 0.99067/2 = 0.495335 moles/liter.