2. A solution is prepared by diluting 0.785 L of 1.262 M potassium sulfate solution with water to a final volume of 2.00 L. a. How many grams of potassium sulfide were dissolved to make the...

2.
A solution is prepared by diluting 0.785 L of 1.262 M potassium sulfate solution with water to a final volume of 2.00 L.
a.
How many grams of potassium sulfide were dissolved to make the original solution?
b.
What is the molarity of potassium sulfide in the diluted solution?

 

 
 

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The solution is prepared by mixing water in 0.785 L of 1.262 M potassium sulfate solution to obtain a final solution with a volume of 2.00 L.

One liter of a 1 M solution of any substance contains one mole of substance in one liter of the solution. 0.785 L of 1.262 M potassium sulfate solution contains 0.785*1.262 = 0.99067 moles of potassium sulfate.

In the final solution the initial amount of potassium sulfate has been dissolved in 2 L of water. This gives a molarity of 0.99067/2 = 0.495335 moles/liter.

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