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To solve this problem, the Ideal gas equation is important. Remember that the ideal gas law states that:
`PV = nRT`
to solve for the volume of Hydrogen gas, we can arrange the equation into:
`V = (nRT)/(P)`
Mass `H_2` = 2.0 grams
P = 0.986 atm (at STP)
T = 273.15 K (at STP)
R = gas constant = 0.08206 `(atm-L)/(mol-K)`
First, we get the number of moles of Hydrogen gas.
`(2.0 grams H_2)* (1 mol e H_2)/(2.016 grams H_2)`
= 0.9921 moles `H_2`
Now we are ready to get the value of the volume.
V = (nRT)/(P)
V = (0.9921*0.08206*273.15)/(0.986atm)
V = 22.6 Liters of `H_2`
The unit of volume can be expressed in many ways. I can also be equal to:
22600 mL; 22600`cm^3` ; 0.0226 cubic meters
note: There are many interpretations of STP, some would say that at STP, the condition of a gas is at 1atm (not 0.986at,) and 273.15 K.
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