`2 - 6ln(x) = 10` Solve the logarithmic equation algebraically. Approximate the result to three decimal places.

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Chapter 3, 3.4 - Problem 51 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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`-6lnx=8 `

`lnx=-4/3 `

Change to `log_e `

`log_(e)x=-4/3 `

`e^(-4/3)=x `

`x=0.264 `

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