`2 - 6ln(x) = 10` Solve the logarithmic equation algebraically. Approximate the result to three decimal places.

loves2learn | Student

`-6lnx=8 `

`lnx=-4/3 `

Change to `log_e `

`log_(e)x=-4/3 `

`e^(-4/3)=x `

`x=0.264 `