`2 + 3ln(x) = 12` Solve the logarithmic equation algebraically. Approximate the result to three decimal places.

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loves2learn | (Level 3) Salutatorian

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`3lnx=10 `

`lnx=10/3 `

Change to `log_e `

`log_(e)x=10/3 `

`e^(10/3)=x `

`x=28.032 `