`2.1 = ln(6x)` Solve the logarithmic equation algebraically. Approximate the result to three decimal places.

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Chapter 3, 3.4 - Problem 47 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Change to `log_e `

`log_(e)6x=2.1 `

`e^2.1=6x `

`x=e^2.1/6 `

`x=1.361 `

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