This is a titration problem where acid is allowed to be neutralized by a base. The chemical equation for this reaction is
HNO3 + NaOH --> H2O + NaNO3
To get the value of the concentration of the nitric acid solution we have to use the amount of NaOH solution...
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This is a titration problem where acid is allowed to be neutralized by a base. The chemical equation for this reaction is
HNO3 + NaOH --> H2O + NaNO3
To get the value of the concentration of the nitric acid solution we have to use the amount of NaOH solution used in the reaction.
In neutralization reaction:
Moles acid = moles base
Therefore:
Moles NaOH = moles HNO3
Remember that, Molarity = moles/volume(L)
So, moles = Molarity * Volume (L)
(Molarity x volume)for NaOH = (Molarity x Volume) for HNO3
Substituting the value of the given:
0.100 moles/L*(12.5/1000)L = Molarity*(50/1000)L
Then we solve for the Molarity of HNO3
Molarity of HNO3 = (0.100x 0.0125)/(0.05)
Molarity of HNO3 = 0.025 moles/L