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cot(x)=1/tan(x) and tan(x)=1/cot(x).
So the left side is cot(x)+tan(x) and the right is tan(x)+cot(x),
which are the same.
By cross multiplication we get,
`1/tanx +1/cotx = (cotx+tanx)/(tanx.cotx) ` = `cotx+tanx` . Since `tanx = 1/cotx.`
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