`1/tan(x) + 1/cot(x) = tan(x) + cot(x)` Verfiy the identity.

Textbook Question

Chapter 5, 5.2 - Problem 27 - Precalculus (3rd Edition, Ron Larson).
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Borys Shumyatskiy | College Teacher | (Level 3) Associate Educator

Posted on

cot(x)=1/tan(x) and tan(x)=1/cot(x).

So the left side is cot(x)+tan(x) and the right is tan(x)+cot(x),

which are the same.

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balajia | College Teacher | (Level 1) eNoter

Posted on

By cross multiplication we get,

`1/tanx +1/cotx = (cotx+tanx)/(tanx.cotx) `  = `cotx+tanx` . Since  `tanx = 1/cotx.`

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