`1/tan(beta) + tan(beta) = [sec^2(beta)]/tan(beta)` Verfiy the identity.

1 Answer

mathace's profile pic

mathace | (Level 3) Assistant Educator

Posted on

Verify the identity: `1/tan(beta)+tan(beta)=[sec^2(beta)]/tan(beta)`

`[1+tan^2(beta)]/tan(beta)=[sec^2(beta)]/tan(beta)`

Use the pythagorean identity `1+tan^2(beta)=sec^2(beta).`

`[sec^2(beta)]/tan(beta)=[sec^2(beta)]/tan(beta)`