`1/tan(beta) + tan(beta) = [sec^2(beta)]/tan(beta)` Verfiy the identity.

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Chapter 5, 5.2 - Problem 20 - Precalculus (3rd Edition, Ron Larson).
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mathace | (Level 3) Assistant Educator

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Verify the identity: `1/tan(beta)+tan(beta)=[sec^2(beta)]/tan(beta)`

`[1+tan^2(beta)]/tan(beta)=[sec^2(beta)]/tan(beta)`

Use the pythagorean identity `1+tan^2(beta)=sec^2(beta).`

`[sec^2(beta)]/tan(beta)=[sec^2(beta)]/tan(beta)`

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