1. State all the non permissible values of the following rational equations: a.  (x-3)(x+4)/(x-3)(x+2)=1/x b.  2x-5/x^2+x+5 PLEASE HELP!!!!

1 Answer

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neela | High School Teacher | (Level 3) Valedictorian

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(x-3)(x+4)/[(x-3)(x+2)}= 1/x. To find non permissible values of x.

x-3 both in numerator and denominator gets cancelled. So we can write the expression:

(x+4)/(x+2) = 1/x. Since the zero in denominator implies division by zero which is not permissible, x+2 = 0 or x=-2 is not permissible. Also there is x in denominator . So x= 0 is not permissible.


Actually 2x-5/x^2+x+5 and  2x-(5/x^2)+x+5 are same.In such a case, x^2 = 0 or x = 0 is not permissible.

If you mea (2x-5)/(x^2+x+5). Then if the denominator x^2+x+5 = 0, then the roots of the equation (if they are real ) are not permissible.

But since the discriminant , (square of coefficient - 4times product od coefficient of x^2 and constant term) = 1^2-4*1*5 = =-19 is negative, there are no real roots and so the expression x^2+x+5 is non zero. So there are no non permissible real values for the given rational expression.