# `1/root(3)((9+1))^2` `I am just having trouble trying to solove this one!`

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llltkl | Student

`1/root(3)((9+1))^2`

= `1/root(3)10^2`

`=10^(-2/3)`

`=0.215443`

**Therefore solution of `1/root(3)((9+1))^2` is 0.215443.**