1) p(m or a then c)2) p(a consonant or i)3) p(t then a)4) p(h then a vowel)the letters in the word mathematics are written on pieces of paper and placed in a hat.a slip of paper is drawn from the...

1) p(m or a then c)

2) p(a consonant or i)

3) p(t then a)

4) p(h then a vowel)

the letters in the word mathematics are written on pieces of paper and placed in a hat.a slip of paper is drawn from the hat.please help me find each of the following probabilities without replacing the letters.

Expert Answers
ladyvols1 eNotes educator| Certified Educator

MATHEMATICS  There are 2 m's and 2 a's so your probabilty of drawing either would be  4/11.  Once you draw one out that would leave 10 letters so your probablity of drawing a "c" would be 1/10.

The chances or probability of drawing a consonant or an "i" would be 8/11 because there are 7 consonants adn one "i".

The probability of drawing a "t" would be 2/11.  After you draw one out, you will have 10 letters left so your probability of drawing an "a" would be 2/10 which reduces to 1/5.

Finally, your probability of drawing an "h"  would be 1/11  then  a vowel would be 4/10 or 2/5 after reducing.

revolution | Student

1) if you pick a m or an a, and there is 2 a and 2m in mathematics, so the probablity would be 4/11. Since you are choosing one out only, there would be 10 left so the probablity of choosing a c out of the remainder, as there is only one C, is 1/10

2) There is 7 consonants and one I so the probablity of choosing them is 8/11

3) The probablity of drawing t would be 2/11 since there are 2 T. If T is drawn out, there would be 10 left so your probablity of drawing an "a" out would be 2/10 =1/5 since there is 2 "a" left.

4) probablity of drawing a "h" out would be 1/11, since there is only one there. Removing one would leave behind 10 alphabets. There is 4 vowels left behinf so p= 4/10= 2/5