1. How to write the expression 243 ^-4/5 in radical notation? Don't evaluate. 2. Evaluate the radical expression. Thank you for your help. Tricia  

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pramodpandey | College Teacher | (Level 3) Valedictorian

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243 ^-4/5 in radical

`(243)^(-4/5)=1/(243^4)^(1/5)`

`=1/root(5)(243^4)`

`B`

`(243)^(-4/5)=(3^5)^(-4/5)`

`=(3)^(5xx(-4/5))`

`=(3)^(-4)`

`=1/(3)^4`

`=1/81`

`Ans.`

pramodpandey's profile pic

pramodpandey | College Teacher | (Level 3) Valedictorian

Posted on

243 ^-4/5 in radical

`(243)^(-4/5)`

`=((243)^4)^(-1/5)`

`=1/((243)^4)^(1/5)`

`=1/root(5)((243)^4)`

 

``B      `(243)^(-4/5)`

`(7^3)^(-4/5)`

`=(7)^(3xx(-4/5))`

`=7^(-12/5)`

`=7^(-2)7^(-2/5)`

`=1/(49root(5)(7^2))`

`=1/(49root(5)49)`

 

``Ans. 

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