(1)graph the equation g(x)=1/3-1/4x (2)describe and correct the error,given the functions f(x)=3x-5and g(x)=1/3-4/3x. (a)f(5)=3(5)-5           (b)g(0)=1/3-4/3           5f=15-5      ...

(1)graph the equation g(x)=1/3-1/4x

(2)describe and correct the error,given the functions f(x)=3x-5and g(x)=1/3-4/3x. (a)f(5)=3(5)-5           (b)g(0)=1/3-4/3

5f=15-5                     =-3/3

5f=10                        =-1

f=2

baxthum8 | High School Teacher | (Level 3) Associate Educator

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#1)  Graph the equation `g(x) = 1/3 - 1/4x`

y-intercept = `(0, 1/3)`

slope = `-1/4`

#2)

a:  `f(x) = 3x - 5`

To find f(5) means to substitute 5 for x. The error is that f was treated as a variable to solve for.  f is not a variable, it is notation for a function.` `

`f(5) = 3(5) - 5`

` ` `f(5) = 15 - 5`

`f(5) = 10`

b:  `g(0) = 1/3 - 4/3x`

Substitute 0 for x.

`g(0) = 1/3 - 4/3(0)`

` ` `g(0) = 1/3 - 0`

`g(0) = 1/3`

The mistake is that 0 was not multiplied by 4/3.  It was treated as nothing and just takin away.