# 2. The area of a rectangle is 3 times the area of a square of side (x+1)cm. The length and breadth of the rectangle are (2x+5)cm and (2x-1)cm respectively.(a) Form an equation and shows that it reduces to x2 + 2x - 8 = 0.  (b) Solve the equation in (a)   3.4x2 + 4xy + y2 - z2 over y2+ 2yz + z2 - 4x2 = ? 1. Given that a2 + 7a = b2 +7b, and that a is not equal to b, find the value of 1/14(a+b).

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A (sq) = `l^2`

A(rect) = l x b

`therefore A=(x+1)^2`  (square) and

`A=(2x+5) times (2x-1)` (retangle)

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Please note that, in terms of eNotes rules, only one question (and one closely related question can be answered at any given time. Please therefore repost your remaining questions as 2 separate posts.

A (sq) = `l^2`

A(rect) = l x b

`therefore A=(x+1)^2`  (square) and

`A=(2x+5) times (2x-1)` (retangle)

But the rectangle is also 3 times the area of the square

`therefore A = 3(x+1)^2`  (rectangle)

`therefore 3(x+1)^2 = (2x+5)(2x-1)`  (these both represent the area of the rectangle). Now simplify:

`therefore 3(x^2 +2x+1 )= 4x^2-2x+10x -5`

`3x^2 +6x +3 = 4x^2 +8x - 5`

Bring everything to the one side:

`therefore 0 = 4x^2-3x^2+8x -6x -5-3`

`0= x^2+2x-8`  which can also be written:

`x^2 +2x -8=0`

Now factorize. Use the factors of `1x^2` and the factors of -8 That is `1x times 1x`  and for the 8 1x8 would not work but 4x2 will work. Care to arrange the symbols correctly. You can check your work if you are ever unsure :

`(x-2)(x+4)=0`

Each factor is equal to zero

`therefore x-2=0 and x+4=0`

`therefore` x=2 and x=-4

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