Let `x^2=4py` be equation of parabola. Then equation of directrix is `y=-p` coordinates of focus are `(0,p)` and axis of symmetry is `y`-axis.
In this case the equation of parabola is
`1/8x^2-y=0`
`1/8x^2=y`
Multiply whole equation by 8 in order to obtain equation in standard form.
`x^2=8y`
Therefore,
`4p=8`
`p=2`
Directrix is line `y=-2` focus is point `(0,2)` and axis pf symmetry is `y`-axis.
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