`1/8x^2-y=0` Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.

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Let `x^2=4py` be equation of parabola. Then equation of directrix is `y=-p`  coordinates of focus are `(0,p)` and axis of symmetry is `y`-axis.

In this case the equation of parabola is

`1/8x^2-y=0`

`1/8x^2=y`

Multiply whole equation by 8 in order to obtain equation in standard form.

`x^2=8y`

Therefore,

`4p=8`

`p=2`

Directrix is line `y=-2` focus...

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Let `x^2=4py` be equation of parabola. Then equation of directrix is `y=-p`  coordinates of focus are `(0,p)` and axis of symmetry is `y`-axis.

In this case the equation of parabola is

`1/8x^2-y=0`

`1/8x^2=y`

Multiply whole equation by 8 in order to obtain equation in standard form.

`x^2=8y`

Therefore,

`4p=8`

`p=2`

Directrix is line `y=-2` focus is point `(0,2)` and axis pf symmetry is `y`-axis. 

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