Numerator contains powers of 2 starting with `2^0=1` while the denominator contains powers of 3 starting with `3^1=3.` Therefore, the `n`th term is

`a_n=2^(n-1)/3^n`

Numerator contains powers of 2 starting with `2^0=1` while the denominator contains powers of 3 starting with `3^1=3.` Therefore, the `n`th term is

`a_n=2^(n-1)/3^n`