A 1.24 × 104 kg railroad car moving at 7.77 m/s to the north collides with and sticks to another railroad car of the same mass. . . that is moving in the same direction at 1.66 m/s. What is the velocity of the joined cars after the collision? Answer in units of m/s

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This is an example of a non-elastic collision. This means that two objects collide and stick together after the collision.

The general form of the equation is:

m1v1  + m2v2 = (m1+m2)v

m1v1 are the mass and velocity of the first object, m2mv2 are the mass and velocity of the...

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This is an example of a non-elastic collision. This means that two objects collide and stick together after the collision.

The general form of the equation is:

m1v1  + m2v2 = (m1+m2)v

m1v1 are the mass and velocity of the first object, m2mv2 are the mass and velocity of the second object, and v is the resultant velocity.

Since both cars are moving in the same direction, both have a positive velocity.

1.24x 10^4 kg * 7.77 m/s + 1.24 x 10^4 * 1.66 m/s = 2.48x10^4 v

v = 4.715 m/s

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