226 Ra decays into Rn (atomic number 86) and alpha particle. complete the
88 reaction written below. be sure to show the atomic mass number
and atomic number of each particle.(alpha particle has two protons
and two neutrons.)
(2) The decay of upper number 226 88 Rn results in the release of some energy .that energy is released in a nuclear reaction when mass is changed to energy .yet there are the same number of nucleons before the decay as there are after the decay .is energy released in this reaction without a conservation of mass ? if not ,what mass is covered?
(B)in what direction would an electron accelerate if it were placed in the electric field in lines of force representation of an electric field?
(C)a carbon sample taken from bone of saber tooth tiger emits 1 beta emission a minute .a carbon sample of the same size taken from fresh piece of bine emits 16 beta emissions a minute. how long ago did the saber tooth tiger live ?
An atom of radium with atomic mass 226 and atomic number 88, `Ra^226_88` , decays to an atom of Radon with atomic number 86. An alpha particle is also emitted during this reaction. An alpha particle is a positively charged helium atom with atomic number 2 and the atomic mass is 4. The reaction can be written as:
`Ra^226_88 -> Rn^222_86 + He^4_2`
The mass-energy equation is E = m*v^2. In the reaction where radium is converted to radon with the emission of an alpha particle, the number of nucleons on both sides of the equation are the same.
A radium atom has an atomic mass 226.025403 and the sum of the mass of a radon atom and an alpha particle is 226.019077. There is a small reduction in mass when a radium atom decays to an atom of radon and an alpha particle. This results in the energy that is released in the decay reaction.