A 1.2 kg ball is accelerated from rest to a speed of 6.5 m/sec. What is change in momentum and the impulse. If a force of 39 N was used to change the momentum for how long did it act.

Expert Answers

An illustration of the letter 'A' in a speech bubbles

The 1.2 kg ball is accelerated from rest to a speed of 6.5 m/s. Momentum is given as the product of mass and velocity. Initially as the ball was at rest the momentum was 0. When it is moving at 6.5 m/s the momentum is 1.2*6.5 = 7.8 kg*m/s. The change in momentum is 7.8 kg*m/s

The impulse that leads to the change in velocity of the ball is 7.8 kg*m/s

If a constant force of 39 N acting on the ball results in the change in its velocity, the product of the time for which it acts and the force itself is equal to the impulse. Or 7.8 = 39*t, t = 7.8/39 = 0.2 s

The force acting for 0.2 s increases changes the velocity of the ball from 0 to 6.5 m/s.

Approved by eNotes Editorial Team
Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial