# 1. A 10ml solution contains 1g of NaCl (a)Find the molarity of Chlorine ions in this solution?

## Expert Answers First we need a balanced chemical reaction which shows the dissociation of NaCl into its ions...

`NaCl -> (Na^+) + (Cl^-)`

Which means one mole of NaCl will produce only one mole of Cl- ions.

Given

1 g of NaCl.

Moles = mass/molar mass

Moles = `1/58.44`

Moles = 0.0171 of NaCl

Which means 1 g of NaCl will produce 0.0171 moles of `Cl^-` .

Molarity = moles/volume in litres.

Molarity = `0.0171/0.01`

Molarity = 1.71 M

Therefore 10 ml of solution containing 1 g of NaCl will 1.71 Molarity of `Cl^-` ions.

Approved by eNotes Editorial Team Molarity means the number of moles dissolved in one litre of solution.

Molar mass

Na = 23 g/mol

Cl = 35 g/mol

NaCl molar mass = 11+17 = 58 g/mol

Moles present in the solution = 1g/58g/mol

= 0.017mol

0.017 moles are in 10ml. Molarity means the number of moles in 1000ml or 1 lire.

So molarity of NaCl = 0.017/10*1000

= 1.7 mol/lL

Molarity of NaCl is 1.7 mol/L

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