1. A 10ml solution contains 1g of NaCl (a)Find the molarity of Chlorine ions in this solution?  

Expert Answers

An illustration of the letter 'A' in a speech bubbles

First we need a balanced chemical reaction which shows the dissociation of NaCl into its ions...

`NaCl -> (Na^+) + (Cl^-)`

Which means one mole of NaCl will produce only one mole of Cl- ions.

Given

1 g of NaCl.

Moles = mass/molar mass

Moles = `1/58.44`

Moles = 0.0171 of NaCl

Which means 1 g of NaCl will produce 0.0171 moles of `Cl^-` .

Molarity = moles/volume in litres.

Molarity = `0.0171/0.01`

Molarity = 1.71 M

Therefore 10 ml of solution containing 1 g of NaCl will 1.71 Molarity of `Cl^-` ions.

Approved by eNotes Editorial Team
An illustration of the letter 'A' in a speech bubbles

Molarity means the number of moles dissolved in one litre of solution.

 

Molar mass

Na = 23 g/mol

Cl = 35 g/mol

 

NaCl molar mass = 11+17 = 58 g/mol

 

Moles present in the solution = 1g/58g/mol

                                          = 0.017mol

 

0.017 moles are in 10ml. Molarity means the number of moles in 1000ml or 1 lire.

 

So molarity of NaCl = 0.017/10*1000

                            = 1.7 mol/lL

 

Molarity of NaCl is 1.7 mol/L

Approved by eNotes Editorial Team
Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial