1. A 10ml solution contains 1g of NaCl (a)Find the molarity of Chlorine ions in this solution?
First we need a balanced chemical reaction which shows the dissociation of NaCl into its ions...
`NaCl -> (Na^+) + (Cl^-)`
Which means one mole of NaCl will produce only one mole of Cl- ions.
1 g of NaCl.
Moles = mass/molar mass
Moles = `1/58.44`
Moles = 0.0171 of NaCl
Which means 1 g of NaCl will produce 0.0171 moles of `Cl^-` .
Molarity = moles/volume in litres.
Molarity = `0.0171/0.01`
Molarity = 1.71 M
Therefore 10 ml of solution containing 1 g of NaCl will 1.71 Molarity of `Cl^-` ions.
Molarity means the number of moles dissolved in one litre of solution.
Na = 23 g/mol
Cl = 35 g/mol
NaCl molar mass = 11+17 = 58 g/mol
Moles present in the solution = 1g/58g/mol
0.017 moles are in 10ml. Molarity means the number of moles in 1000ml or 1 lire.
So molarity of NaCl = 0.017/10*1000
= 1.7 mol/lL
Molarity of NaCl is 1.7 mol/L
1g of Nacl ( = na= 23 & cl=35.5)( 23+35.5= 58.5)
WELL , NICE QUESTION .... WE HAVE MOLE CONCEPT AS A CHAPTER IN CHEMISTRY
No. of moles = given mass / molecular mass
= 1/ 58.5
1Molar solution is a solution having 1mole of solute and 1 litre of solvent
1 L = 1000 ml
x L = 10 ml
x = 10 * 1/ 1000 = 0.01 L
MOLARITY = 0.017 / 0.01 = 1.7 M