If 0.74 g of O3 reacts with 0.67 g of NO to form O2 and NO2 , how many grams of NO2 will be produced?
It is given that 0.74 g of O3 reacts with 0.67 g of NO to form O2 and NO2. The chemical equation of this reaction is:
NO + O3 --> NO2 + O2
The molar mass of nitrogen is 14 and that of oxygen is 16.
This gives the molar mass of O3 as 48 and that of NO as 30.
From the molar mass of the reactants and the chemical equation of the reaction you have given, 0.74 g of O3 reacts with 0.4625 g of NO, not 0.67 g.
The mass of NO that is reacting is incorrect.
When 0.74g of O3 reacts with NO, we get approximately 0.709 g of NO2.