0.406 g of antacid, active ingredient Ca(HCO3)2 treated with excess HCl gives 86.44 mL of CO2 at 25.00oC, 1.000 atm. What % is active ingredient? Asumme a perfect system (i.e 100% yield)
We can solve this problem by employing the ideal gas law.
PV = nRT
P = pressure (atm) = 1.000 atm
V = volume (L) = (86.44mL/1000mL)L
n = number of moles = ?
R = gas constant, 0.08206 atm-L/mol/K
T = temperature (in Kelvin) = 25.00 + 273.15 = 298.15K
n = PV/RT =...
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