0.250 g of an element, M, reacts with excess fluorine to produce 0.547 g of the hexafluoride, MF6. What is the element?
First we have to do the chemical reaction of the unknown element ‘M’ with fluorine.
`M + F_2 -> MF_6`
Balancing it will make it:
`M + 3 F_2 -> MF_6`
We assume that all of the mass of the element M is consumed.
(The entire section contains 118 words.)
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