A 0.240 kg blob of clay is thrown at a wall with in an initial velocity of 23 m/s . If the clay comes to a stop in 91.0 ms .What is the average force experienced by the clay?
From the equation of impulse we get:
Here, m = 0.240 kg, v= 23 m/s and t = 91.0 ms = 91*10^-3 s. Now, plugging in the values in the above relation we get:
`F * 91*10^-3 = 0.240*23 `
`rArr F = (0.240*23) /(91*10^-3)`
`rArr F=60.65934 N`
`rArr F~~61 N`
Hence, the average force experienced by the clay is 61 N.