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tjbrewer | Elementary School Teacher | (Level 2) Associate Educator

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I would assume that you're supposed to solve `.16x-41=3/7 x+6` to find x. 

Step 1: choose to use decimal or Fractions.  Since `3/7` is a repeating decimal (i.e. an 'ugly' decimal according to a College Professor of mine), we should use fractions. 

Step 2: convert the decimal to a fraction.  `.16=16/100=4/25` So your new equation is `4/25 x-41=3/7 x+6`

Step 3: Get x on one side of the equation.  You can subtract either fraction with x from both sides of the equation.  I personally would subtract 4/25x from both sides. 
Step 3a: find the LCM of 25 and 7, which is 175. 
Step 3b: convert fractions to equivalent fractions with like denominators.  `4/25 = 28/175` & `3/7 = 75/175`
`75/175 - 28/175 = 47/125` The new equation then is this:`-41=47/125 x+6`

Step 4: Subtract 6 from both sides yielding `-47=47/125 x`

Step 5: Divide both sides by 47/125 yielding x.  `-47-:47/125 =-47/1xx125/47=-125`
The solution x=-125