A 0.160 kg hockey puck starts from rest and reaches a speed of 22 m/s when a hockey stick pushes on it for 1.2 m during a shot. Determine the average net force on the puck using two different methods?
- print Print
- list Cite
Expert Answers
Rylan Hills
| Certified Educator
calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
The hockey puck has a mass 0.16 kg. It starts from rest and reaches a speed of 22 m/s, during which the distance traveled is 1.2 m.
Initially the puck has no kinetic energy. After 1.2 m the kinetic energy is (1/2)*m*v^2 = .5*0.16*22^2 = 38.72. Let the net average force be F, the work done on the puck is F*d = F*1.2 = 38.72
=> F = 32.27 N
Another way of determining the force is to use the relation v^2 - u^2 = 2*a*s where s is the total distance traveled, u is the initial velocity, v is the final velocity and a is the acceleration.
22^2 = 2*a*1.2
=> a = 605/3
The force applied is 0.16*605/3 = 32.27 N
Related Questions
- A hockey player accelerates a puck of 0.167 kg from rest to 50 m/s in 0.0121 sec. Determine the...
- 1 Educator Answer
- A hockey puck on a frozen pond with an initial speed of 18.50 m/s stops after sliding a distance...
- 1 Educator Answer
- Is a hockey stick used as lever? What kind of lever is it?
- 1 Educator Answer
- Calculate the change in the total kinetic energy of the system that occurs during the following...
- 1 Educator Answer
- Questions based on circular motionAn air puck of mass 0.034 kg is tied to a string and allowed to...
- 1 Educator Answer