Math at eNotes
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The latest questions and answers, from members following Math at eNotes.Sat, 10 Oct 2015 04:34:03 PSTen-us`cos(arcsin(2x))` let `theta = arcsin(2x)` so we need to find...
http://www.enotes.com/homework-help/cos-arcsin-2x-write-an-algebraic-expression-that-521620
`cos(arcsin(2x))` let `theta = arcsin(2x)` so we need to find `cos(theta)` As ` theta = arcsin(2x)` `sin(theta)= 2x = (2x)/1 = (opposite side) / (hypotenuse)` by using the right triangle we get the hypotenuse as =1 so, the adjacent side = sqrt(hypotenuse ^2 - opposite side^2) `= sqrt(1-(2x)^2)` =sqrt(1-4x^2) so` cos(theta)` = adjacent side/hypotenuse = `sqrt(1-4x^2)/1`http://www.enotes.com/homework-help/cos-arcsin-2x-write-an-algebraic-expression-that-521620Sat, 10 Oct 2015 04:34:03 PSTNot able to understand how the final value of derivative =2/5 did not...
http://www.enotes.com/homework-help/x-3-y-3-6xy-1-2-3-find-dy-dx-by-implicit-521280
Not able to understand how the final value of derivative =2/5 did not appeared.http://www.enotes.com/homework-help/x-3-y-3-6xy-1-2-3-find-dy-dx-by-implicit-521280Sat, 10 Oct 2015 04:28:20 PST`sin(arctan(x))` let `theta = arctan(x)` => `tan(theta)=x= x/1` by...
http://www.enotes.com/homework-help/sin-arctan-x-write-an-algebraic-expression-that-521619
`sin(arctan(x))` let `theta = arctan(x)` => `tan(theta)=x= x/1` by using the right triangle we get the hypotenuse is `= sqrt(1+x^2)` so `sin(theta) = x/(sqrt(1+x^2))`http://www.enotes.com/homework-help/sin-arctan-x-write-an-algebraic-expression-that-521619Sat, 10 Oct 2015 03:53:16 PSTThe formula to change the base of the log would be so that would...
http://www.enotes.com/homework-help/f-x-log-2-x-use-change-base-formula-rewrite-521502
The formula to change the base of the log would be so that would translate to : = `logx/log2` ` `Refer to the attachement below for the graph.Hope this helped!http://www.enotes.com/homework-help/f-x-log-2-x-use-change-base-formula-rewrite-521502Sat, 10 Oct 2015 01:02:09 PSTGiven: `x^3+y^3=6xy-1,(2,3)` `3x^2+3y^2dy/dx=6xdy/dx+y(6)`...
http://www.enotes.com/homework-help/x-3-y-3-6xy-1-2-3-find-dy-dx-by-implicit-521280
Given: `x^3+y^3=6xy-1,(2,3)` `3x^2+3y^2dy/dx=6xdy/dx+y(6)` `3y^2dy/dx-6xdy/dx=6y-3x^2` `dy/dx(3y^2-6x)=6y-3x^2` `dy/dx=(6y-3x^2)/(3y^2-6x)` `dy/dx=[3(2y-x^2)]/[3(y^2-2x)]` `dy/dx=(2y-x^2)/(y^2-2x)` Evaluate the derivative by substituting the (2, 3) into the derivative. `dy/dx=[2(3)-(2)^2]/[(3)^2-2(2)]=2/5`http://www.enotes.com/homework-help/x-3-y-3-6xy-1-2-3-find-dy-dx-by-implicit-521280#1Fri, 9 Oct 2015 19:07:40 PSTGiven: `f(x)=root(3)(x), [-8, 8]` Find the critical values for x by...
http://www.enotes.com/homework-help/g-x-root-3-x-8-8-find-absolute-extrema-function-521374
Given: `f(x)=root(3)(x), [-8, 8]` Find the critical values for x by setting the derivative equal to zero and solving for the x value(s). `f(x)=x^(1/3)` `f'(x)=(1/3)x^(-2/3)=0 ` ` f'(x)=1/(3x^(2/3))=0` ` 1=0 ` 1=0 is not a true statement. Therefore the critical x value(s) does not exist. Plug in the critical value(s), if one exists, and the endpoints of the interval into f(x). `f(x)=root(3)(x)` `f(8)=root(3)(8)=2` `f(-8)=root(3)(-8)=-2`...http://www.enotes.com/homework-help/g-x-root-3-x-8-8-find-absolute-extrema-function-521374Fri, 9 Oct 2015 18:44:45 PSTGiven: `f(x)=2x^3-6x,[0, 3]` Find the critical values for x by setting...
http://www.enotes.com/homework-help/f-x-2x-3-6x-0-3-find-absolute-extrema-function-521372
Given: `f(x)=2x^3-6x,[0, 3]` Find the critical values for x by setting the derivative equal to zero and solving for the x value(s). `f'(x)=6x^2-6=0` `6(x^2-1)=0` `6(x+1)(x-1)=0` `x=-1, x=1` The critical values for x are x=1 and x=-1. Plug in the critical value(s) and the endpoints of the interval into f(x). Because x=-1 is not in the interval [0, 3], it is not necessary to plug in the x=-1 `f(x)=2x^3-6x` `f(0)=2(0)^3-6(0)=0`...http://www.enotes.com/homework-help/f-x-2x-3-6x-0-3-find-absolute-extrema-function-521372Fri, 9 Oct 2015 18:28:47 PST`x^2+y^2=9` convert into polar coordinates `x=3cos(theta)`...
http://www.enotes.com/homework-help/x-2-y-2-9-find-dy-dx-by-implicit-differentiation-521259
`x^2+y^2=9` convert into polar coordinates `x=3cos(theta)` `y=3sin(theta)` `dy/(d(theta))=3cos(theta) ` `dx/(d(theta))=-3sin(theta) ` `dy/dx=-x/y` ``http://www.enotes.com/homework-help/x-2-y-2-9-find-dy-dx-by-implicit-differentiation-521259Fri, 9 Oct 2015 17:56:51 PST`sec(sin^-1 (-sqrt(2)/2))` `Let theta = sin^-1 (-sqrt(2)/2)` so we need...
http://www.enotes.com/homework-help/sec-sin-1-sqrt-2-2-find-exact-value-expression-521617
`sec(sin^-1 (-sqrt(2)/2))` `Let theta = sin^-1 (-sqrt(2)/2)` so we need to find `sec (theta)` => `sin(theta) = (-sqrt(2)/2)` =>` sin(theta) = -1/sqrt(2)` we know `sin^2(theta) +cos^2(theta) = 1` =>` (-1/sqrt(2))^2 + cos^2(theta) = 1` =>` (1/2)+cos^2(theta) = 1` => `cos^2(theta) = 1-1/2 =1/2` =>` cos(theta) = 1/(sqrt(2))` so , `sec(theta) = sqrt(2)`http://www.enotes.com/homework-help/sec-sin-1-sqrt-2-2-find-exact-value-expression-521617Fri, 9 Oct 2015 16:16:59 PST`cos(sin^(-1)(2x)) = cos(cos^(-1)(sqrt(1-(2x)^2)))`...
http://www.enotes.com/homework-help/cos-arcsin-2x-write-an-algebraic-expression-that-521620
`cos(sin^(-1)(2x)) = cos(cos^(-1)(sqrt(1-(2x)^2)))` `=cos(cos^(-1)(sqrt(1-4x^2)))` `=sqrt(1-4x^2)`http://www.enotes.com/homework-help/cos-arcsin-2x-write-an-algebraic-expression-that-521620#2Fri, 9 Oct 2015 13:15:11 PST`sin(cos^(-1)x) = sin(sin^(-1)(sqrt(1-x^2)))` `= sqrt(1-x^2)`
http://www.enotes.com/homework-help/sin-arccos-x-write-an-algebraic-expression-that-521622
`sin(cos^(-1)x) = sin(sin^(-1)(sqrt(1-x^2)))` `= sqrt(1-x^2)`http://www.enotes.com/homework-help/sin-arccos-x-write-an-algebraic-expression-that-521622Fri, 9 Oct 2015 13:12:53 PSTYou have to notice the dependence of the amounts to every specific units...
http://www.enotes.com/homework-help/3-workers-can-build-3-houses-3-days-how-many-523871
You have to notice the dependence of the amounts to every specific units which are given to you. We have 3:3:3 to 12:12:... ; the ration has increased 4 times. You have to implement that information, and here you are, the outcome is 48 houses in 12 days. As the 3 workers has been doing job in 3 day it has been 3 houses (roughly one house done by one worker) - there 12 workers in 12 days (ration increased by 4) that's why we multiply those by 4...http://www.enotes.com/homework-help/3-workers-can-build-3-houses-3-days-how-many-523871Fri, 9 Oct 2015 10:42:18 PSTSorry -- a=b=1 so a+b=2
http://www.enotes.com/homework-help/please-help-524122
Sorry -- a=b=1 so a+b=2http://www.enotes.com/homework-help/please-help-524122Fri, 9 Oct 2015 01:57:15 PSTWe are given the graph of f(x) -- it looks like a parabola (but may not...
http://www.enotes.com/homework-help/please-help-524122
We are given the graph of f(x) -- it looks like a parabola (but may not be one) with vertex at (4,-3) opening down. We are given g(x)=-f(x+3)-3. Note that the graph of g(x) is the graph of f(x) translated 3 units to the left, reflected over the x-axis, and then translated 3 units down. Thus the point (4,-3) is mapped to the point (1,0) with the rest of the graph opening up. So g(x) has one x-intercept. As f(x) is a function (given), f(x)...http://www.enotes.com/homework-help/please-help-524122#3Fri, 9 Oct 2015 01:56:11 PSTplease help
http://www.enotes.com/homework-help/please-help-524122
please helphttp://www.enotes.com/homework-help/please-help-524122#4October 9, 2015, 1:00 am PST