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Question:

landishigh
landishigh
Student
College - Freshman

A monovalent ion enters into a plane-parallel capacitor. The entrance angle, alfa=30 degrees,up against armatures.Find the kinetik energy of the ion.

The ion comes out by keeping the same entrance angle(the value is positive).

The length of capacitor is l=10cm and electric field intensity, E=40KV/m.

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Posted by landishigh on Monday June 29, 2009 at 2:03 AM and tagged with armature, electric field intensity, length, monovalent, science.

Answers:

  1. giorgiana1976
    giorgiana1976 Teacher
    Doctorate

    eNotes Editor

    Best answer as selected by question asker.

    The problem is analogue to oblique projection in gravitational field, the only difference being that instead of gravitational acceleration g, we'll have the acceleration a=e*E/m

    Then, the length of capacitor represents "tha range"

    l=(v0^2/a)*sin 2 alfa=[m*v0^2/(e*E)]*sin 2 alfa

    The kinetic energy is the semiproduct between the weight of the particle and it's square speed:

    Ek=m*v0^2/2=e*E*l/(2 sin 2 alfa=0.37fJ=2.3KeV

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    Posted by giorgiana1976 on Monday June 29, 2009 at 12:23 PM