Science Group
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eNotes Editor
Posted by doabbott3 on Friday October 9, 2009 at 9:39 PMAmazing.... I assume this answer is much too late; however, for posterity (and to prove myself?); here goes.... (I might mention that simply doing the problem for you may have very little impact on your learning to do it yourself; you should try, hard, to do as much as you can BEFORE you ask...?)
The general equilibrium equation constant, (1X10^-4) is equal to the mathematical product of the concentration of products [NO] , in mole/L, raised to the respective power of their coefficients, 2; Divided by the product of the concentrations of the reactants, [N2] & [O2] raised to the respective power of their coefficients:
1X10^-4 = [NO]^2/ {[N2][O2]}
Initial Concentrations of N2 and O2 = 1M; NO= 0M
If X amount of N2 and O2 react then:
Equilibrium concentrations of N2 and O2 = [1-X]
Equilibrium concentration of NO = 2X
So since 1X10^-4 is small; not much reacts so "X" is gonna be small; therefore [1-X] =~1
Therefore: 1X10^-4 = [2X]^2 /{[1][1}
and 1X10^-4 = 4X^2 or 1X10^-4 /4 = X^2 or 25X 10^-6 = X^2 or 5X10^-3 = X so [NO] = 2X = [1X10^-2]


