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gudeapp
gudeapp
Student
College - Freshman

Calculate the kinetic energy of a proton which moves into a field of induction B=167mT, on a circle with radius r=50cm.

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Posted by gudeapp on Wednesday July 1, 2009 at 3:03 AM and tagged with field, induction, kinetic energy, proton, radius, science.

Answers:

  1. giorgiana1976
    giorgiana1976 Teacher
    Doctorate

    eNotes Editor

    Lorentz force is acting on electron, so lex secunda is giving the followings:

    module (q*vxB)=e*v*B=m*ac=m*v^2/r, so v=(r/m)*e*B

    Ec=m*v^2/2=(e*B*r)^2/(2*m)=53.4fJ=0.334MeV

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    Posted by giorgiana1976 on Tuesday July 7, 2009 at 9:31 AM