Science Group
Question:
Answers:
-
eNotes Editor
Posted by giorgiana1976 on Monday June 29, 2009 at 10:50 AMBest answer as selected by question asker.
P=R[nE/(R+r*n)]^2=R[E/(R+r/n)]^2, so R=r
P=R[nE/(R+R*n)]^2=(E^2/R)[n/(n+1)^2]
P1=R[E/(R+R)]^2=E^2/(4R)=(P/4)[(n+1)/n]^2
P1=4.0W

