lochana2500
lochana2500
Male
May 22, 2012
Student
High School - 12th Grade
Mathematics
Mathematics , Chemistry , Physics
Biography
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New Activity for lochana2500
Answered a Question in Math
lim x→0 (1-cosx)/x² = lim x→0 [(1-cosx)(1+cosx)]/[x²(1+cosx)] = {lim x→0...
Answered a Question in Math
sinΘ = 3/5 ----(1) cosΘ = 4/5 ----(2) (1)/(2) sinΘ/cosΘ = tanΘ =...
Answered a Question in Math
Answered a Question in Math
sin²A/a² = (1-cos²A) ÷ a² = { 1-[(b²+c²-a²)/2bc]² } ÷ a² =...
Answered a Question in Chemistry
Answered a Question in Science
Asked a Question in Chemistry
NaOH + Al + NaNO₂→ NaAlO₂+ NH₃+ H2O 1). What are the Redox reactions of...
Answered a Question in History
No i didn't mean that..I didn't reply to your question..It's my post to this...
Answered a Question in History
Answered a Question in Math
Answered a Question in Math
Answered a Question in Math
a+b+c=π a+b=π-c ∴ a/2 + b/2 = π/2 - c/2 sin(a/2+b/2) = sin(π/2-c/2)...
Answered a Question in Math
Got the answer... L:H:S = sin(5π/24) = sin(π/3 - π/8) = sin π/3.cos...
Earned a Badge
Answered a Question in Math
Asked a Question in Math
if cos(A-B) + cos(B-C) + cos(C-A) = -3/2 Prove cos A + cos B + cos C = sin A + sin...
Answered a Question in Math
tan(x+pi/3) = (tanx + tan pi/3)/(1-tanx.tan pi/6) we know that tan pi/6 = √3 ,...
Answered a Question in Math
tan 2x = 2tanx / (1 - tan²x) We know that tanx= √2 = 2√2 /...
Answered a Question in Math
tan (a-b) = (tan a - tan b) / (1 + tan a.tan b) We know that : tan a = 3/4,...
Answered a Question in Math
cot a = 2 ∴ tana = 1/2 cot b = 5 ∴ tanb = 1/5 tan (a+b) = (tana...
Answered a Question in trigonometry math
tan 2x = 2tanx / (1 - tan²x) tan 2x = [2*(2/3)]/[1-(2/3)²] = (4/3) /...
Answered a Question in Math
tan(x-pi) = (tanx - tan pi)/(1-tanx.tan pi) we know that tan pi = 0 = (tanx -...
Answered a Question in Math
tan (45+360) = (tan 45 + tan 360)/(1-tan45.tan360) we know that tan 360 = tan 0 =...
Answered a Question in Math
tan (x+pi) = (tanx +tan pi)/(1-tanx.tan pi) we know that tan pi = 0 = (tanx +...
Answered a Question in Math
L:H:S = [tan(x+y)-tany]/[1+tan(x+y)tany] ⇒ (tanA - tanB) / (1 + tanA.tanB)...
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