Math Group
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Posted by jlcannad on Thursday May 28, 2009 at 1:10 PMI can't answer x+3y=6 right now. I have two variables (x and Y) so I'm stuck.
So, I turn to my other equation. y-3=7. If I add three to each side of the equation, I get y=10.
Now that I know y=10, I can put the number 10 in every place there was a "y." So, the second equation looks like this...
x+3y=6
x+3(10)=6
x+30=6 So I subtract 30 from each side.
x=-24
I then check myself by putting all my numbers back into the original equations.
10-3=7 and -24+3(10)=6
Yep, that works.
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Posted by emplay on Thursday May 28, 2009 at 1:13 PM

