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Question:


dogcrazy
Student
High School - 10th Grade

What is the product of the slopes of perpendicular lines and why is this product always negative?

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Posted by dogcrazy on Sunday November 1, 2009 at 2:19 PM and tagged with geometry, math.


Answers:

  1. kjcdb8er
    kjcdb8er Teacher

    eNotes Editor

    If the slope of a line is m, then the slope of a line perpendicular to it is -1/m.

    So, m * -1/m = -1

    This number is always negative because: a negative times a positive is always negative. If m is negative, then -1/m is positive.

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    Posted by kjcdb8er on Sunday November 1, 2009 at 2:50 PM

  2. neela
    neela Teacher
    Graduate School

    eNotes Editor

    Let the equation of the two lines be:

    y=m1*x+c1 and

    y=m2*x+c2, where m1 and m2 are the slopes of the lines and c1 and c2 are their  intercepts on the Y axis.

    The angles A and B by the above two the lines with X axis is given by:

    tanA = m1 and tan B = m2.

    Therefore, the angle between the two lines, B-A is given by:

    Tan(A-B) = (tanA-tanB)/{1+tanA*tanB}.............(1)

    When A-B is a right angle  or 90 degrees, Tan(A-B) is tan 90 degrees , which should be infinite. Or the denominator on the right side of equation at (1)  is zero  or 1+tanA*tan B =0  or tanA*tan B=-1 or m1*m2=-1 or the product of the slope must be equal to minus one.

    So,the  product of the slopes of the lines is mimus one, when they are at right angles or perpendicular to each other.

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    Posted by neela on Sunday November 1, 2009 at 5:33 PM