Math Group
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eNotes Editor
Posted by neela on Tuesday May 26, 2009 at 10:53 PMx-2/x+6=x/2 . Multiplying by 2x both sides, we get
2x^2-4+ 12x=x^2. Subtract x^2 from both sides to get,
2x^2-x^2 -4 +12x =0 =>
[x^2+12x]-4 =0=>
[(x+6)^2-36] -4 = 0=>
(x+6)^2 -40=0=>
(x+6)^2 = 40=>
x+6 = +sqrt(40)=2sqrt(10) or x=-sqrt(40) = -2sqrt(10)
Therefore,
x= -6+2srt(10) =0.3246 nearly
or
x=-6-2sqrt(10) = -12.3246 nearly'
NB:
I do not recommend this which is wrong . But many people have a tendency to do this way by voluntarily imposing brackets as below:
(x-2)/(x+6) = x/2 . Mutiplying by 2(x+6)
2(x-2) = x(x+6)=>
2x-4=x^2+6x=>
0=x^2+6x-2x+4 =>
0=x^2+4x+4 or 0 = (x+2)^2 =>
x+2 = 0 or
x=-2 is a double root.
Looks nice and simple. But volunteering to impose a bracket like this change the given expression.

